Line slope calculator 5x-3y=17
Straight line given by points A[4; 1] and B[7; 6]
Calculation:
Slope: m = 1.6667Slope-intercept form of line: y = 1.6667x-5.6667
Canonical form of the line equation: 5x-3y-17 = 0
Parametric form of the line equation:
x = 3t+4
y = 5t+1 ; t ∈ R
Slope angle of line: φ = 59°2'10″ = 1.0304 rad
X intercept: x0 = 3.4
Y intercept: y0 = q = -5.6667
Distance line from the origin: d0 = 2.9155
The length of the segment AB: |AB| = 5.831
Vector: AB = (3; 5)
Normal vector: n = (5; -3)
Midpoint of the segment AB: M = [5.5; 3.5]
Perpendicular Bisector equation: 3x+5y-34 = 0
Vector OA = (4; 1) ; |OA| = 4.1231
Vector OB = (7; 6) ; |OB| = 9.2195
Scalar product OA .OB = 34
Angle ∠ AOB = 26°33'54″ = 0.4636 rad