Line slope calculator 5x-4y=16


Enter coordinates of two different points:

Straight line given by points A[4; 1] and B[8; 6]

Calculation:

Slope-intercept form of line: y = 1.25x-4

Canonical form of the line equation: 5x-4y-16 = 0

Parametric form of the line equation:
x = 4t+4
y = 5t+1      ; t ∈ R

Slope: m = 1.25

Slope angle of line: φ = 51°20'25″ = 0.8961 rad

X intercept: x0 = 3.2

Y intercept: y0 = q = -4

Distance line from the origin: d0 = 2.4988

The length of the segment AB: |AB| = 6.4031

Vector: AB = (4; 5)

Normal vector: n = (5; -4)

Midpoint of the segment AB: M = [6; 3.5]

Perpendicular Bisector equation: 4x+5y-41.5 = 0


Vector OA = (4; 1) ;   |OA| = 4.1231
Vector OB = (8; 6) ;   |OB| = 10
Scalar product OA .OB = 38
Angle ∠ AOB = 22°50'1″ = 0.3985 rad