Line slope calculator 5x-4y=16
Straight line given by points A[4; 1] and B[8; 6]
Calculation:
Slope: m = 1.25Slope-intercept form of line: y = 1.25x-4
Canonical form of the line equation: 5x-4y-16 = 0
Parametric form of the line equation:
x = 4t+4
y = 5t+1 ; t ∈ R
Slope angle of line: φ = 51°20'25″ = 0.8961 rad
X intercept: x0 = 3.2
Y intercept: y0 = q = -4
Distance line from the origin: d0 = 2.4988
The length of the segment AB: |AB| = 6.4031
Vector: AB = (4; 5)
Normal vector: n = (5; -4)
Midpoint of the segment AB: M = [6; 3.5]
Perpendicular Bisector equation: 4x+5y-41.5 = 0
Vector OA = (4; 1) ; |OA| = 4.1231
Vector OB = (8; 6) ; |OB| = 10
Scalar product OA .OB = 38
Angle ∠ AOB = 22°50'1″ = 0.3985 rad