Line slope calculator x+5y=9


Enter coordinates of two different points:

Straight line given by points A[4; 1] and B[9; 0]

Calculation:

Slope-intercept form of line: y = -0.2x+1.8

Canonical form of the line equation: x+5y-9 = 0

Parametric form of the line equation:
x = 5t+4
y = -t+1      ; t ∈ R

Slope: m = -0.2

Slope angle of line: φ = -11°18'36″ = -0.1974 rad

X intercept: x0 = 9

Y intercept: y0 = q = 1.8

Distance line from the origin: d0 = 1.765

The length of the segment AB: |AB| = 5.099

Vector: AB = (5; -1)

Normal vector: n = (1; 5)

Midpoint of the segment AB: M = [6.5; 0.5]

Perpendicular Bisector equation: 5x-y-32 = 0


Vector OA = (4; 1) ;   |OA| = 4.1231
Vector OB = (9; 0) ;   |OB| = 9
Scalar product OA .OB = 36
Angle ∠ AOB = 14°2'10″ = 0.245 rad