Line slope calculator 4x-5y=11
Straight line given by points A[4; 1] and B[9; 5]
Calculation:
Slope: m = 0.8Slope-intercept form of line: y = 0.8x-2.2
Canonical form of the line equation: 4x-5y-11 = 0
Parametric form of the line equation:
x = 5t+4
y = 4t+1 ; t ∈ R
Slope angle of line: φ = 38°39'35″ = 0.6747 rad
X intercept: x0 = 2.75
Y intercept: y0 = q = -2.2
Distance line from the origin: d0 = 1.7179
The length of the segment AB: |AB| = 6.4031
Vector: AB = (5; 4)
Normal vector: n = (4; -5)
Midpoint of the segment AB: M = [6.5; 3]
Perpendicular Bisector equation: 5x+4y-44.5 = 0
Vector OA = (4; 1) ; |OA| = 4.1231
Vector OB = (9; 5) ; |OB| = 10.2956
Scalar product OA .OB = 41
Angle ∠ AOB = 15°1'6″ = 0.2621 rad