Line slope calculator 4x-5y=11


Enter coordinates of two different points:

Straight line given by points A[4; 1] and B[9; 5]

Calculation:

Slope-intercept form of line: y = 0.8x-2.2

Canonical form of the line equation: 4x-5y-11 = 0

Parametric form of the line equation:
x = 5t+4
y = 4t+1      ; t ∈ R

Slope: m = 0.8

Slope angle of line: φ = 38°39'35″ = 0.6747 rad

X intercept: x0 = 2.75

Y intercept: y0 = q = -2.2

Distance line from the origin: d0 = 1.7179

The length of the segment AB: |AB| = 6.4031

Vector: AB = (5; 4)

Normal vector: n = (4; -5)

Midpoint of the segment AB: M = [6.5; 3]

Perpendicular Bisector equation: 5x+4y-44.5 = 0


Vector OA = (4; 1) ;   |OA| = 4.1231
Vector OB = (9; 5) ;   |OB| = 10.2956
Scalar product OA .OB = 41
Angle ∠ AOB = 15°1'6″ = 0.2621 rad