Line slope calculator 5x+6y=80
Straight line given by points A[4; 10] and B[10; 5]
Calculation:
Slope: m = -0.8333Slope-intercept form of line: y = -0.8333x+13.3333
Canonical form of the line equation: 5x+6y-80 = 0
Parametric form of the line equation:
x = 6t+4
y = -5t+10 ; t ∈ R
Slope angle of line: φ = -39°48'20″ = -0.6947 rad
X intercept: x0 = 16
Y intercept: y0 = q = 13.3333
Distance line from the origin: d0 = 10.243
The length of the segment AB: |AB| = 7.8102
Vector: AB = (6; -5)
Normal vector: n = (5; 6)
Midpoint of the segment AB: M = [7; 7.5]
Perpendicular Bisector equation: 6x-5y-4.5 = 0
Vector OA = (4; 10) ; |OA| = 10.7703
Vector OB = (10; 5) ; |OB| = 11.1803
Scalar product OA .OB = 90
Angle ∠ AOB = 41°38'1″ = 0.7266 rad