Line slope calculator 10x+y=50


Enter coordinates of two different points:

Straight line given by points A[4; 10] and B[5; 0]

Calculation:

Slope-intercept form of line: y = -10x+50

Canonical form of the line equation: 10x+y-50 = 0

Parametric form of the line equation:
x = t+4
y = -10t+10      ; t ∈ R

Slope: m = -10

Slope angle of line: φ = -84°17'22″ = -1.4711 rad

X intercept: x0 = 5

Y intercept: y0 = q = 50

Distance line from the origin: d0 = 4.9752

The length of the segment AB: |AB| = 10.0499

Vector: AB = (1; -10)

Normal vector: n = (10; 1)

Midpoint of the segment AB: M = [4.5; 5]

Perpendicular Bisector equation: x-10y+45.5 = 0


Vector OA = (4; 10) ;   |OA| = 10.7703
Vector OB = (5; 0) ;   |OB| = 5
Scalar product OA .OB = 20
Angle ∠ AOB = 68°11'55″ = 1.1903 rad