Line slope calculator 10x+y=50
Straight line given by points A[4; 10] and B[5; 0]
Calculation:
Slope: m = -10Slope-intercept form of line: y = -10x+50
Canonical form of the line equation: 10x+y-50 = 0
Parametric form of the line equation:
x = t+4
y = -10t+10 ; t ∈ R
Slope angle of line: φ = -84°17'22″ = -1.4711 rad
X intercept: x0 = 5
Y intercept: y0 = q = 50
Distance line from the origin: d0 = 4.9752
The length of the segment AB: |AB| = 10.0499
Vector: AB = (1; -10)
Normal vector: n = (10; 1)
Midpoint of the segment AB: M = [4.5; 5]
Perpendicular Bisector equation: x-10y+45.5 = 0
Vector OA = (4; 10) ; |OA| = 10.7703
Vector OB = (5; 0) ; |OB| = 5
Scalar product OA .OB = 20
Angle ∠ AOB = 68°11'55″ = 1.1903 rad