Line slope calculator 8x+y=42


Enter coordinates of two different points:

Straight line given by points A[4; 10] and B[5; 2]

Calculation:

Slope-intercept form of line: y = -8x+42

Canonical form of the line equation: 8x+y-42 = 0

Parametric form of the line equation:
x = t+4
y = -8t+10      ; t ∈ R

Slope: m = -8

Slope angle of line: φ = -82°52'30″ = -1.4464 rad

X intercept: x0 = 5.25

Y intercept: y0 = q = 42

Distance line from the origin: d0 = 5.2095

The length of the segment AB: |AB| = 8.0623

Vector: AB = (1; -8)

Normal vector: n = (8; 1)

Midpoint of the segment AB: M = [4.5; 6]

Perpendicular Bisector equation: x-8y+43.5 = 0


Vector OA = (4; 10) ;   |OA| = 10.7703
Vector OB = (5; 2) ;   |OB| = 5.3852
Scalar product OA .OB = 40
Angle ∠ AOB = 46°23'50″ = 0.8098 rad