Line slope calculator 7x+y=38


Enter coordinates of two different points:

Straight line given by points A[4; 10] and B[5; 3]

Calculation:

Slope-intercept form of line: y = -7x+38

Canonical form of the line equation: 7x+y-38 = 0

Parametric form of the line equation:
x = t+4
y = -7t+10      ; t ∈ R

Slope: m = -7

Slope angle of line: φ = -81°52'12″ = -1.4289 rad

X intercept: x0 = 5.4286

Y intercept: y0 = q = 38

Distance line from the origin: d0 = 5.374

The length of the segment AB: |AB| = 7.0711

Vector: AB = (1; -7)

Normal vector: n = (7; 1)

Midpoint of the segment AB: M = [4.5; 6.5]

Perpendicular Bisector equation: x-7y+41 = 0


Vector OA = (4; 10) ;   |OA| = 10.7703
Vector OB = (5; 3) ;   |OB| = 5.831
Scalar product OA .OB = 50
Angle ∠ AOB = 37°14'5″ = 0.6499 rad