Line slope calculator 5x+y=30


Enter coordinates of two different points:

Straight line given by points A[4; 10] and B[5; 5]

Calculation:

Slope-intercept form of line: y = -5x+30

Canonical form of the line equation: 5x+y-30 = 0

Parametric form of the line equation:
x = t+4
y = -5t+10      ; t ∈ R

Slope: m = -5

Slope angle of line: φ = -78°41'24″ = -1.3734 rad

X intercept: x0 = 6

Y intercept: y0 = q = 30

Distance line from the origin: d0 = 5.8835

The length of the segment AB: |AB| = 5.099

Vector: AB = (1; -5)

Normal vector: n = (5; 1)

Midpoint of the segment AB: M = [4.5; 7.5]

Perpendicular Bisector equation: x-5y+33 = 0


Vector OA = (4; 10) ;   |OA| = 10.7703
Vector OB = (5; 5) ;   |OB| = 7.0711
Scalar product OA .OB = 70
Angle ∠ AOB = 23°11'55″ = 0.4049 rad