Line slope calculator 5x+2y=40
Straight line given by points A[4; 10] and B[6; 5]
Calculation:
Slope: m = -2.5Slope-intercept form of line: y = -2.5x+20
Canonical form of the line equation: 5x+2y-40 = 0
Parametric form of the line equation:
x = 2t+4
y = -5t+10 ; t ∈ R
Slope angle of line: φ = -68°11'55″ = -1.1903 rad
X intercept: x0 = 8
Y intercept: y0 = q = 20
Distance line from the origin: d0 = 7.4278
The length of the segment AB: |AB| = 5.3852
Vector: AB = (2; -5)
Normal vector: n = (5; 2)
Midpoint of the segment AB: M = [5; 7.5]
Perpendicular Bisector equation: 2x-5y+27.5 = 0
Vector OA = (4; 10) ; |OA| = 10.7703
Vector OB = (6; 5) ; |OB| = 7.8102
Scalar product OA .OB = 74
Angle ∠ AOB = 28°23'35″ = 0.4956 rad