Line slope calculator 5x+2y=40


Enter coordinates of two different points:

Straight line given by points A[4; 10] and B[6; 5]

Calculation:

Slope-intercept form of line: y = -2.5x+20

Canonical form of the line equation: 5x+2y-40 = 0

Parametric form of the line equation:
x = 2t+4
y = -5t+10      ; t ∈ R

Slope: m = -2.5

Slope angle of line: φ = -68°11'55″ = -1.1903 rad

X intercept: x0 = 8

Y intercept: y0 = q = 20

Distance line from the origin: d0 = 7.4278

The length of the segment AB: |AB| = 5.3852

Vector: AB = (2; -5)

Normal vector: n = (5; 2)

Midpoint of the segment AB: M = [5; 7.5]

Perpendicular Bisector equation: 2x-5y+27.5 = 0


Vector OA = (4; 10) ;   |OA| = 10.7703
Vector OB = (6; 5) ;   |OB| = 7.8102
Scalar product OA .OB = 74
Angle ∠ AOB = 28°23'35″ = 0.4956 rad