Line slope calculator 2x+3y=38


Enter coordinates of two different points:

Straight line given by points A[4; 10] and B[7; 8]

Calculation:

Slope-intercept form of line: y = -0.6667x+12.6667

Canonical form of the line equation: 2x+3y-38 = 0

Parametric form of the line equation:
x = 3t+4
y = -2t+10      ; t ∈ R

Slope: m = -0.6667

Slope angle of line: φ = -33°41'24″ = -0.588 rad

X intercept: x0 = 19

Y intercept: y0 = q = 12.6667

Distance line from the origin: d0 = 10.5393

The length of the segment AB: |AB| = 3.6056

Vector: AB = (3; -2)

Normal vector: n = (2; 3)

Midpoint of the segment AB: M = [5.5; 9]

Perpendicular Bisector equation: 3x-2y+1.5 = 0


Vector OA = (4; 10) ;   |OA| = 10.7703
Vector OB = (7; 8) ;   |OB| = 10.6301
Scalar product OA .OB = 108
Angle ∠ AOB = 19°23'4″ = 0.3383 rad