Line slope calculator 2x+4y=48


Enter coordinates of two different points:

Straight line given by points A[4; 10] and B[8; 8]

Calculation:

Slope-intercept form of line: y = -0.5x+12

Canonical form of the line equation: 2x+4y-48 = 0

Parametric form of the line equation:
x = 4t+4
y = -2t+10      ; t ∈ R

Slope: m = -0.5

Slope angle of line: φ = -26°33'54″ = -0.4636 rad

X intercept: x0 = 24

Y intercept: y0 = q = 12

Distance line from the origin: d0 = 10.7331

The length of the segment AB: |AB| = 4.4721

Vector: AB = (4; -2)

Normal vector: n = (2; 4)

Midpoint of the segment AB: M = [6; 9]

Perpendicular Bisector equation: 4x-2y-6 = 0


Vector OA = (4; 10) ;   |OA| = 10.7703
Vector OB = (8; 8) ;   |OB| = 11.3137
Scalar product OA .OB = 112
Angle ∠ AOB = 23°11'55″ = 0.4049 rad