Line slope calculator 7x+5y=78
Straight line given by points A[4; 10] and B[9; 3]
Calculation:
Slope: m = -1.4Slope-intercept form of line: y = -1.4x+15.6
Canonical form of the line equation: 7x+5y-78 = 0
Parametric form of the line equation:
x = 5t+4
y = -7t+10 ; t ∈ R
Slope angle of line: φ = -54°27'44″ = -0.9505 rad
X intercept: x0 = 11.1429
Y intercept: y0 = q = 15.6
Distance line from the origin: d0 = 9.0673
The length of the segment AB: |AB| = 8.6023
Vector: AB = (5; -7)
Normal vector: n = (7; 5)
Midpoint of the segment AB: M = [6.5; 6.5]
Perpendicular Bisector equation: 5x-7y+13 = 0
Vector OA = (4; 10) ; |OA| = 10.7703
Vector OB = (9; 3) ; |OB| = 9.4868
Scalar product OA .OB = 66
Angle ∠ AOB = 49°45'49″ = 0.8685 rad