Line slope calculator x+6y=16
Straight line given by points A[4; 2] and B[10; 1]
Calculation:
Slope: m = -0.1667Slope-intercept form of line: y = -0.1667x+2.6667
Canonical form of the line equation: x+6y-16 = 0
Parametric form of the line equation:
x = 6t+4
y = -t+2 ; t ∈ R
Slope angle of line: φ = -9°27'44″ = -0.1651 rad
X intercept: x0 = 16
Y intercept: y0 = q = 2.6667
Distance line from the origin: d0 = 2.6304
The length of the segment AB: |AB| = 6.0828
Vector: AB = (6; -1)
Normal vector: n = (1; 6)
Midpoint of the segment AB: M = [7; 1.5]
Perpendicular Bisector equation: 6x-y-40.5 = 0
Vector OA = (4; 2) ; |OA| = 4.4721
Vector OB = (10; 1) ; |OB| = 10.0499
Scalar product OA .OB = 42
Angle ∠ AOB = 20°51'16″ = 0.364 rad