Line slope calculator 2x+5y=18


Enter coordinates of two different points:

Straight line given by points A[4; 2] and B[9; 0]

Calculation:

Slope-intercept form of line: y = -0.4x+3.6

Canonical form of the line equation: 2x+5y-18 = 0

Parametric form of the line equation:
x = 5t+4
y = -2t+2      ; t ∈ R

Slope: m = -0.4

Slope angle of line: φ = -21°48'5″ = -0.3805 rad

X intercept: x0 = 9

Y intercept: y0 = q = 3.6

Distance line from the origin: d0 = 3.3425

The length of the segment AB: |AB| = 5.3852

Vector: AB = (5; -2)

Normal vector: n = (2; 5)

Midpoint of the segment AB: M = [6.5; 1]

Perpendicular Bisector equation: 5x-2y-30.5 = 0


Vector OA = (4; 2) ;   |OA| = 4.4721
Vector OB = (9; 0) ;   |OB| = 9
Scalar product OA .OB = 36
Angle ∠ AOB = 26°33'54″ = 0.4636 rad