Line slope calculator 2x+5y=18
Straight line given by points A[4; 2] and B[9; 0]
Calculation:
Slope: m = -0.4Slope-intercept form of line: y = -0.4x+3.6
Canonical form of the line equation: 2x+5y-18 = 0
Parametric form of the line equation:
x = 5t+4
y = -2t+2 ; t ∈ R
Slope angle of line: φ = -21°48'5″ = -0.3805 rad
X intercept: x0 = 9
Y intercept: y0 = q = 3.6
Distance line from the origin: d0 = 3.3425
The length of the segment AB: |AB| = 5.3852
Vector: AB = (5; -2)
Normal vector: n = (2; 5)
Midpoint of the segment AB: M = [6.5; 1]
Perpendicular Bisector equation: 5x-2y-30.5 = 0
Vector OA = (4; 2) ; |OA| = 4.4721
Vector OB = (9; 0) ; |OB| = 9
Scalar product OA .OB = 36
Angle ∠ AOB = 26°33'54″ = 0.4636 rad