Line slope calculator 7x-3y=19
Straight line given by points A[4; 3] and B[7; 10]
Calculation:
Slope: m = 2.3333Slope-intercept form of line: y = 2.3333x-6.3333
Canonical form of the line equation: 7x-3y-19 = 0
Parametric form of the line equation:
x = 3t+4
y = 7t+3 ; t ∈ R
Slope angle of line: φ = 66°48'5″ = 1.1659 rad
X intercept: x0 = 2.7143
Y intercept: y0 = q = -6.3333
Distance line from the origin: d0 = 2.4948
The length of the segment AB: |AB| = 7.6158
Vector: AB = (3; 7)
Normal vector: n = (7; -3)
Midpoint of the segment AB: M = [5.5; 6.5]
Perpendicular Bisector equation: 3x+7y-62 = 0
Vector OA = (4; 3) ; |OA| = 5
Vector OB = (7; 10) ; |OB| = 12.2066
Scalar product OA .OB = 58
Angle ∠ AOB = 18°8'17″ = 0.3166 rad