Line slope calculator 7x-3y=19


Enter coordinates of two different points:

Straight line given by points A[4; 3] and B[7; 10]

Calculation:

Slope-intercept form of line: y = 2.3333x-6.3333

Canonical form of the line equation: 7x-3y-19 = 0

Parametric form of the line equation:
x = 3t+4
y = 7t+3      ; t ∈ R

Slope: m = 2.3333

Slope angle of line: φ = 66°48'5″ = 1.1659 rad

X intercept: x0 = 2.7143

Y intercept: y0 = q = -6.3333

Distance line from the origin: d0 = 2.4948

The length of the segment AB: |AB| = 7.6158

Vector: AB = (3; 7)

Normal vector: n = (7; -3)

Midpoint of the segment AB: M = [5.5; 6.5]

Perpendicular Bisector equation: 3x+7y-62 = 0


Vector OA = (4; 3) ;   |OA| = 5
Vector OB = (7; 10) ;   |OB| = 12.2066
Scalar product OA .OB = 58
Angle ∠ AOB = 18°8'17″ = 0.3166 rad