Line slope calculator 5x-3y=11


Enter coordinates of two different points:

Straight line given by points A[4; 3] and B[7; 8]

Calculation:

Slope-intercept form of line: y = 1.6667x-3.6667

Canonical form of the line equation: 5x-3y-11 = 0

Parametric form of the line equation:
x = 3t+4
y = 5t+3      ; t ∈ R

Slope: m = 1.6667

Slope angle of line: φ = 59°2'10″ = 1.0304 rad

X intercept: x0 = 2.2

Y intercept: y0 = q = -3.6667

Distance line from the origin: d0 = 1.8865

The length of the segment AB: |AB| = 5.831

Vector: AB = (3; 5)

Normal vector: n = (5; -3)

Midpoint of the segment AB: M = [5.5; 5.5]

Perpendicular Bisector equation: 3x+5y-44 = 0


Vector OA = (4; 3) ;   |OA| = 5
Vector OB = (7; 8) ;   |OB| = 10.6301
Scalar product OA .OB = 52
Angle ∠ AOB = 11°56'39″ = 0.2085 rad