Line slope calculator 3x+5y=27


Enter coordinates of two different points:

Straight line given by points A[4; 3] and B[9; 0]

Calculation:

Slope-intercept form of line: y = -0.6x+5.4

Canonical form of the line equation: 3x+5y-27 = 0

Parametric form of the line equation:
x = 5t+4
y = -3t+3      ; t ∈ R

Slope: m = -0.6

Slope angle of line: φ = -30°57'50″ = -0.5404 rad

X intercept: x0 = 9

Y intercept: y0 = q = 5.4

Distance line from the origin: d0 = 4.6305

The length of the segment AB: |AB| = 5.831

Vector: AB = (5; -3)

Normal vector: n = (3; 5)

Midpoint of the segment AB: M = [6.5; 1.5]

Perpendicular Bisector equation: 5x-3y-28 = 0


Vector OA = (4; 3) ;   |OA| = 5
Vector OB = (9; 0) ;   |OB| = 9
Scalar product OA .OB = 36
Angle ∠ AOB = 36°52'12″ = 0.6435 rad