Line slope calculator 3x+5y=27
Straight line given by points A[4; 3] and B[9; 0]
Calculation:
Slope: m = -0.6Slope-intercept form of line: y = -0.6x+5.4
Canonical form of the line equation: 3x+5y-27 = 0
Parametric form of the line equation:
x = 5t+4
y = -3t+3 ; t ∈ R
Slope angle of line: φ = -30°57'50″ = -0.5404 rad
X intercept: x0 = 9
Y intercept: y0 = q = 5.4
Distance line from the origin: d0 = 4.6305
The length of the segment AB: |AB| = 5.831
Vector: AB = (5; -3)
Normal vector: n = (3; 5)
Midpoint of the segment AB: M = [6.5; 1.5]
Perpendicular Bisector equation: 5x-3y-28 = 0
Vector OA = (4; 3) ; |OA| = 5
Vector OB = (9; 0) ; |OB| = 9
Scalar product OA .OB = 36
Angle ∠ AOB = 36°52'12″ = 0.6435 rad