Line slope calculator 7x-5y=13
Straight line given by points A[4; 3] and B[9; 10]
Calculation:
Slope: m = 1.4Slope-intercept form of line: y = 1.4x-2.6
Canonical form of the line equation: 7x-5y-13 = 0
Parametric form of the line equation:
x = 5t+4
y = 7t+3 ; t ∈ R
Slope angle of line: φ = 54°27'44″ = 0.9505 rad
X intercept: x0 = 1.8571
Y intercept: y0 = q = -2.6
Distance line from the origin: d0 = 1.5112
The length of the segment AB: |AB| = 8.6023
Vector: AB = (5; 7)
Normal vector: n = (7; -5)
Midpoint of the segment AB: M = [6.5; 6.5]
Perpendicular Bisector equation: 5x+7y-78 = 0
Vector OA = (4; 3) ; |OA| = 5
Vector OB = (9; 10) ; |OB| = 13.4536
Scalar product OA .OB = 66
Angle ∠ AOB = 11°8'34″ = 0.1945 rad