Line slope calculator 7x-5y=13


Enter coordinates of two different points:

Straight line given by points A[4; 3] and B[9; 10]

Calculation:

Slope-intercept form of line: y = 1.4x-2.6

Canonical form of the line equation: 7x-5y-13 = 0

Parametric form of the line equation:
x = 5t+4
y = 7t+3      ; t ∈ R

Slope: m = 1.4

Slope angle of line: φ = 54°27'44″ = 0.9505 rad

X intercept: x0 = 1.8571

Y intercept: y0 = q = -2.6

Distance line from the origin: d0 = 1.5112

The length of the segment AB: |AB| = 8.6023

Vector: AB = (5; 7)

Normal vector: n = (7; -5)

Midpoint of the segment AB: M = [6.5; 6.5]

Perpendicular Bisector equation: 5x+7y-78 = 0


Vector OA = (4; 3) ;   |OA| = 5
Vector OB = (9; 10) ;   |OB| = 13.4536
Scalar product OA .OB = 66
Angle ∠ AOB = 11°8'34″ = 0.1945 rad