Line slope calculator x+5y=19
Straight line given by points A[4; 3] and B[9; 2]
Calculation:
Slope: m = -0.2Slope-intercept form of line: y = -0.2x+3.8
Canonical form of the line equation: x+5y-19 = 0
Parametric form of the line equation:
x = 5t+4
y = -t+3 ; t ∈ R
Slope angle of line: φ = -11°18'36″ = -0.1974 rad
X intercept: x0 = 19
Y intercept: y0 = q = 3.8
Distance line from the origin: d0 = 3.7262
The length of the segment AB: |AB| = 5.099
Vector: AB = (5; -1)
Normal vector: n = (1; 5)
Midpoint of the segment AB: M = [6.5; 2.5]
Perpendicular Bisector equation: 5x-y-30 = 0
Vector OA = (4; 3) ; |OA| = 5
Vector OB = (9; 2) ; |OB| = 9.2195
Scalar product OA .OB = 42
Angle ∠ AOB = 24°20'28″ = 0.4248 rad