Line slope calculator x+6y=28


Enter coordinates of two different points:

Straight line given by points A[4; 4] and B[10; 3]

Calculation:

Slope-intercept form of line: y = -0.1667x+4.6667

Canonical form of the line equation: x+6y-28 = 0

Parametric form of the line equation:
x = 6t+4
y = -t+4      ; t ∈ R

Slope: m = -0.1667

Slope angle of line: φ = -9°27'44″ = -0.1651 rad

X intercept: x0 = 28

Y intercept: y0 = q = 4.6667

Distance line from the origin: d0 = 4.6032

The length of the segment AB: |AB| = 6.0828

Vector: AB = (6; -1)

Normal vector: n = (1; 6)

Midpoint of the segment AB: M = [7; 3.5]

Perpendicular Bisector equation: 6x-y-38.5 = 0


Vector OA = (4; 4) ;   |OA| = 5.6569
Vector OB = (10; 3) ;   |OB| = 10.4403
Scalar product OA .OB = 52
Angle ∠ AOB = 28°18'3″ = 0.4939 rad