Line slope calculator 3x+4y=28


Enter coordinates of two different points:

Straight line given by points A[4; 4] and B[8; 1]

Calculation:

Slope-intercept form of line: y = -0.75x+7

Canonical form of the line equation: 3x+4y-28 = 0

Parametric form of the line equation:
x = 4t+4
y = -3t+4      ; t ∈ R

Slope: m = -0.75

Slope angle of line: φ = -36°52'12″ = -0.6435 rad

X intercept: x0 = 9.3333

Y intercept: y0 = q = 7

Distance line from the origin: d0 = 5.6

The length of the segment AB: |AB| = 5

Vector: AB = (4; -3)

Normal vector: n = (3; 4)

Midpoint of the segment AB: M = [6; 2.5]

Perpendicular Bisector equation: 4x-3y-16.5 = 0


Vector OA = (4; 4) ;   |OA| = 5.6569
Vector OB = (8; 1) ;   |OB| = 8.0623
Scalar product OA .OB = 36
Angle ∠ AOB = 37°52'30″ = 0.661 rad