Line slope calculator 3x+4y=28
Straight line given by points A[4; 4] and B[8; 1]
Calculation:
Slope: m = -0.75Slope-intercept form of line: y = -0.75x+7
Canonical form of the line equation: 3x+4y-28 = 0
Parametric form of the line equation:
x = 4t+4
y = -3t+4 ; t ∈ R
Slope angle of line: φ = -36°52'12″ = -0.6435 rad
X intercept: x0 = 9.3333
Y intercept: y0 = q = 7
Distance line from the origin: d0 = 5.6
The length of the segment AB: |AB| = 5
Vector: AB = (4; -3)
Normal vector: n = (3; 4)
Midpoint of the segment AB: M = [6; 2.5]
Perpendicular Bisector equation: 4x-3y-16.5 = 0
Vector OA = (4; 4) ; |OA| = 5.6569
Vector OB = (8; 1) ; |OB| = 8.0623
Scalar product OA .OB = 36
Angle ∠ AOB = 37°52'30″ = 0.661 rad