Line slope calculator 4x+5y=36


Enter coordinates of two different points:

Straight line given by points A[4; 4] and B[9; 0]

Calculation:

Slope-intercept form of line: y = -0.8x+7.2

Canonical form of the line equation: 4x+5y-36 = 0

Parametric form of the line equation:
x = 5t+4
y = -4t+4      ; t ∈ R

Slope: m = -0.8

Slope angle of line: φ = -38°39'35″ = -0.6747 rad

X intercept: x0 = 9

Y intercept: y0 = q = 7.2

Distance line from the origin: d0 = 5.6223

The length of the segment AB: |AB| = 6.4031

Vector: AB = (5; -4)

Normal vector: n = (4; 5)

Midpoint of the segment AB: M = [6.5; 2]

Perpendicular Bisector equation: 5x-4y-24.5 = 0


Vector OA = (4; 4) ;   |OA| = 5.6569
Vector OB = (9; 0) ;   |OB| = 9
Scalar product OA .OB = 36
Angle ∠ AOB = 45° = 0.7854 rad