Line slope calculator 3x+5y=32
Straight line given by points A[4; 4] and B[9; 1]
Calculation:
Slope: m = -0.6Slope-intercept form of line: y = -0.6x+6.4
Canonical form of the line equation: 3x+5y-32 = 0
Parametric form of the line equation:
x = 5t+4
y = -3t+4 ; t ∈ R
Slope angle of line: φ = -30°57'50″ = -0.5404 rad
X intercept: x0 = 10.6667
Y intercept: y0 = q = 6.4
Distance line from the origin: d0 = 5.488
The length of the segment AB: |AB| = 5.831
Vector: AB = (5; -3)
Normal vector: n = (3; 5)
Midpoint of the segment AB: M = [6.5; 2.5]
Perpendicular Bisector equation: 5x-3y-25 = 0
Vector OA = (4; 4) ; |OA| = 5.6569
Vector OB = (9; 1) ; |OB| = 9.0554
Scalar product OA .OB = 40
Angle ∠ AOB = 38°39'35″ = 0.6747 rad