Line slope calculator x+5y=24
Straight line given by points A[4; 4] and B[9; 3]
Calculation:
Slope: m = -0.2Slope-intercept form of line: y = -0.2x+4.8
Canonical form of the line equation: x+5y-24 = 0
Parametric form of the line equation:
x = 5t+4
y = -t+4 ; t ∈ R
Slope angle of line: φ = -11°18'36″ = -0.1974 rad
X intercept: x0 = 24
Y intercept: y0 = q = 4.8
Distance line from the origin: d0 = 4.7068
The length of the segment AB: |AB| = 5.099
Vector: AB = (5; -1)
Normal vector: n = (1; 5)
Midpoint of the segment AB: M = [6.5; 3.5]
Perpendicular Bisector equation: 5x-y-29 = 0
Vector OA = (4; 4) ; |OA| = 5.6569
Vector OB = (9; 3) ; |OB| = 9.4868
Scalar product OA .OB = 48
Angle ∠ AOB = 26°33'54″ = 0.4636 rad