Line slope calculator 5x+6y=50
Straight line given by points A[4; 5] and B[10; 0]
Calculation:
Slope: m = -0.8333Slope-intercept form of line: y = -0.8333x+8.3333
Canonical form of the line equation: 5x+6y-50 = 0
Parametric form of the line equation:
x = 6t+4
y = -5t+5 ; t ∈ R
Slope angle of line: φ = -39°48'20″ = -0.6947 rad
X intercept: x0 = 10
Y intercept: y0 = q = 8.3333
Distance line from the origin: d0 = 6.4018
The length of the segment AB: |AB| = 7.8102
Vector: AB = (6; -5)
Normal vector: n = (5; 6)
Midpoint of the segment AB: M = [7; 2.5]
Perpendicular Bisector equation: 6x-5y-29.5 = 0
Vector OA = (4; 5) ; |OA| = 6.4031
Vector OB = (10; 0) ; |OB| = 10
Scalar product OA .OB = 40
Angle ∠ AOB = 51°20'25″ = 0.8961 rad