Line slope calculator 4x+3y=31
Straight line given by points A[4; 5] and B[7; 1]
Calculation:
Slope: m = -1.3333Slope-intercept form of line: y = -1.3333x+10.3333
Canonical form of the line equation: 4x+3y-31 = 0
Parametric form of the line equation:
x = 3t+4
y = -4t+5 ; t ∈ R
Slope angle of line: φ = -53°7'48″ = -0.9273 rad
X intercept: x0 = 7.75
Y intercept: y0 = q = 10.3333
Distance line from the origin: d0 = 6.2
The length of the segment AB: |AB| = 5
Vector: AB = (3; -4)
Normal vector: n = (4; 3)
Midpoint of the segment AB: M = [5.5; 3]
Perpendicular Bisector equation: 3x-4y-4.5 = 0
Vector OA = (4; 5) ; |OA| = 6.4031
Vector OB = (7; 1) ; |OB| = 7.0711
Scalar product OA .OB = 33
Angle ∠ AOB = 43°12'36″ = 0.7542 rad