Line slope calculator 3x+5y=37
Straight line given by points A[4; 5] and B[9; 2]
Calculation:
Slope: m = -0.6Slope-intercept form of line: y = -0.6x+7.4
Canonical form of the line equation: 3x+5y-37 = 0
Parametric form of the line equation:
x = 5t+4
y = -3t+5 ; t ∈ R
Slope angle of line: φ = -30°57'50″ = -0.5404 rad
X intercept: x0 = 12.3333
Y intercept: y0 = q = 7.4
Distance line from the origin: d0 = 6.3454
The length of the segment AB: |AB| = 5.831
Vector: AB = (5; -3)
Normal vector: n = (3; 5)
Midpoint of the segment AB: M = [6.5; 3.5]
Perpendicular Bisector equation: 5x-3y-22 = 0
Vector OA = (4; 5) ; |OA| = 6.4031
Vector OB = (9; 2) ; |OB| = 9.2195
Scalar product OA .OB = 46
Angle ∠ AOB = 38°48'41″ = 0.6774 rad