Line slope calculator 2x+5y=33


Enter coordinates of two different points:

Straight line given by points A[4; 5] and B[9; 3]

Calculation:

Slope-intercept form of line: y = -0.4x+6.6

Canonical form of the line equation: 2x+5y-33 = 0

Parametric form of the line equation:
x = 5t+4
y = -2t+5      ; t ∈ R

Slope: m = -0.4

Slope angle of line: φ = -21°48'5″ = -0.3805 rad

X intercept: x0 = 16.5

Y intercept: y0 = q = 6.6

Distance line from the origin: d0 = 6.1279

The length of the segment AB: |AB| = 5.3852

Vector: AB = (5; -2)

Normal vector: n = (2; 5)

Midpoint of the segment AB: M = [6.5; 4]

Perpendicular Bisector equation: 5x-2y-24.5 = 0


Vector OA = (4; 5) ;   |OA| = 6.4031
Vector OB = (9; 3) ;   |OB| = 9.4868
Scalar product OA .OB = 51
Angle ∠ AOB = 32°54'19″ = 0.5743 rad