Line slope calculator x+5y=29


Enter coordinates of two different points:

Straight line given by points A[4; 5] and B[9; 4]

Calculation:

Slope-intercept form of line: y = -0.2x+5.8

Canonical form of the line equation: x+5y-29 = 0

Parametric form of the line equation:
x = 5t+4
y = -t+5      ; t ∈ R

Slope: m = -0.2

Slope angle of line: φ = -11°18'36″ = -0.1974 rad

X intercept: x0 = 29

Y intercept: y0 = q = 5.8

Distance line from the origin: d0 = 5.6874

The length of the segment AB: |AB| = 5.099

Vector: AB = (5; -1)

Normal vector: n = (1; 5)

Midpoint of the segment AB: M = [6.5; 4.5]

Perpendicular Bisector equation: 5x-y-28 = 0


Vector OA = (4; 5) ;   |OA| = 6.4031
Vector OB = (9; 4) ;   |OB| = 9.8489
Scalar product OA .OB = 56
Angle ∠ AOB = 27°22'40″ = 0.4778 rad