Line slope calculator x+6y=40


Enter coordinates of two different points:

Straight line given by points A[4; 6] and B[10; 5]

Calculation:

Slope-intercept form of line: y = -0.1667x+6.6667

Canonical form of the line equation: x+6y-40 = 0

Parametric form of the line equation:
x = 6t+4
y = -t+6      ; t ∈ R

Slope: m = -0.1667

Slope angle of line: φ = -9°27'44″ = -0.1651 rad

X intercept: x0 = 40

Y intercept: y0 = q = 6.6667

Distance line from the origin: d0 = 6.576

The length of the segment AB: |AB| = 6.0828

Vector: AB = (6; -1)

Normal vector: n = (1; 6)

Midpoint of the segment AB: M = [7; 5.5]

Perpendicular Bisector equation: 6x-y-36.5 = 0


Vector OA = (4; 6) ;   |OA| = 7.2111
Vector OB = (10; 5) ;   |OB| = 11.1803
Scalar product OA .OB = 70
Angle ∠ AOB = 29°44'42″ = 0.5191 rad