Line slope calculator 6x+y=30


Enter coordinates of two different points:

Straight line given by points A[4; 6] and B[5; 0]

Calculation:

Slope-intercept form of line: y = -6x+30

Canonical form of the line equation: 6x+y-30 = 0

Parametric form of the line equation:
x = t+4
y = -6t+6      ; t ∈ R

Slope: m = -6

Slope angle of line: φ = -80°32'16″ = -1.4056 rad

X intercept: x0 = 5

Y intercept: y0 = q = 30

Distance line from the origin: d0 = 4.932

The length of the segment AB: |AB| = 6.0828

Vector: AB = (1; -6)

Normal vector: n = (6; 1)

Midpoint of the segment AB: M = [4.5; 3]

Perpendicular Bisector equation: x-6y+13.5 = 0


Vector OA = (4; 6) ;   |OA| = 7.2111
Vector OB = (5; 0) ;   |OB| = 5
Scalar product OA .OB = 20
Angle ∠ AOB = 56°18'36″ = 0.9828 rad