Line slope calculator 6x+y=30
Straight line given by points A[4; 6] and B[5; 0]
Calculation:
Slope: m = -6Slope-intercept form of line: y = -6x+30
Canonical form of the line equation: 6x+y-30 = 0
Parametric form of the line equation:
x = t+4
y = -6t+6 ; t ∈ R
Slope angle of line: φ = -80°32'16″ = -1.4056 rad
X intercept: x0 = 5
Y intercept: y0 = q = 30
Distance line from the origin: d0 = 4.932
The length of the segment AB: |AB| = 6.0828
Vector: AB = (1; -6)
Normal vector: n = (6; 1)
Midpoint of the segment AB: M = [4.5; 3]
Perpendicular Bisector equation: x-6y+13.5 = 0
Vector OA = (4; 6) ; |OA| = 7.2111
Vector OB = (5; 0) ; |OB| = 5
Scalar product OA .OB = 20
Angle ∠ AOB = 56°18'36″ = 0.9828 rad