Line slope calculator 5x+y=26
Straight line given by points A[4; 6] and B[5; 1]
Calculation:
Slope: m = -5Slope-intercept form of line: y = -5x+26
Canonical form of the line equation: 5x+y-26 = 0
Parametric form of the line equation:
x = t+4
y = -5t+6 ; t ∈ R
Slope angle of line: φ = -78°41'24″ = -1.3734 rad
X intercept: x0 = 5.2
Y intercept: y0 = q = 26
Distance line from the origin: d0 = 5.099
The length of the segment AB: |AB| = 5.099
Vector: AB = (1; -5)
Normal vector: n = (5; 1)
Midpoint of the segment AB: M = [4.5; 3.5]
Perpendicular Bisector equation: x-5y+13 = 0
Vector OA = (4; 6) ; |OA| = 7.2111
Vector OB = (5; 1) ; |OB| = 5.099
Scalar product OA .OB = 26
Angle ∠ AOB = 45° = 0.7854 rad