Line slope calculator 5x+y=26


Enter coordinates of two different points:

Straight line given by points A[4; 6] and B[5; 1]

Calculation:

Slope-intercept form of line: y = -5x+26

Canonical form of the line equation: 5x+y-26 = 0

Parametric form of the line equation:
x = t+4
y = -5t+6      ; t ∈ R

Slope: m = -5

Slope angle of line: φ = -78°41'24″ = -1.3734 rad

X intercept: x0 = 5.2

Y intercept: y0 = q = 26

Distance line from the origin: d0 = 5.099

The length of the segment AB: |AB| = 5.099

Vector: AB = (1; -5)

Normal vector: n = (5; 1)

Midpoint of the segment AB: M = [4.5; 3.5]

Perpendicular Bisector equation: x-5y+13 = 0


Vector OA = (4; 6) ;   |OA| = 7.2111
Vector OB = (5; 1) ;   |OB| = 5.099
Scalar product OA .OB = 26
Angle ∠ AOB = 45° = 0.7854 rad