Line slope calculator 3x+y=18
Straight line given by points A[4; 6] and B[5; 3]
Calculation:
Slope: m = -3Slope-intercept form of line: y = -3x+18
Canonical form of the line equation: 3x+y-18 = 0
Parametric form of the line equation:
x = t+4
y = -3t+6 ; t ∈ R
Slope angle of line: φ = -71°33'54″ = -1.249 rad
X intercept: x0 = 6
Y intercept: y0 = q = 18
Distance line from the origin: d0 = 5.6921
The length of the segment AB: |AB| = 3.1623
Vector: AB = (1; -3)
Normal vector: n = (3; 1)
Midpoint of the segment AB: M = [4.5; 4.5]
Perpendicular Bisector equation: x-3y+9 = 0
Vector OA = (4; 6) ; |OA| = 7.2111
Vector OB = (5; 3) ; |OB| = 5.831
Scalar product OA .OB = 38
Angle ∠ AOB = 25°20'46″ = 0.4424 rad