Line slope calculator 5x+2y=32


Enter coordinates of two different points:

Straight line given by points A[4; 6] and B[6; 1]

Calculation:

Slope-intercept form of line: y = -2.5x+16

Canonical form of the line equation: 5x+2y-32 = 0

Parametric form of the line equation:
x = 2t+4
y = -5t+6      ; t ∈ R

Slope: m = -2.5

Slope angle of line: φ = -68°11'55″ = -1.1903 rad

X intercept: x0 = 6.4

Y intercept: y0 = q = 16

Distance line from the origin: d0 = 5.9423

The length of the segment AB: |AB| = 5.3852

Vector: AB = (2; -5)

Normal vector: n = (5; 2)

Midpoint of the segment AB: M = [5; 3.5]

Perpendicular Bisector equation: 2x-5y+7.5 = 0


Vector OA = (4; 6) ;   |OA| = 7.2111
Vector OB = (6; 1) ;   |OB| = 6.0828
Scalar product OA .OB = 30
Angle ∠ AOB = 46°50'51″ = 0.8176 rad