Line slope calculator 3x+4y=36
Straight line given by points A[4; 6] and B[8; 3]
Calculation:
Slope: m = -0.75Slope-intercept form of line: y = -0.75x+9
Canonical form of the line equation: 3x+4y-36 = 0
Parametric form of the line equation:
x = 4t+4
y = -3t+6 ; t ∈ R
Slope angle of line: φ = -36°52'12″ = -0.6435 rad
X intercept: x0 = 12
Y intercept: y0 = q = 9
Distance line from the origin: d0 = 7.2
The length of the segment AB: |AB| = 5
Vector: AB = (4; -3)
Normal vector: n = (3; 4)
Midpoint of the segment AB: M = [6; 4.5]
Perpendicular Bisector equation: 4x-3y-10.5 = 0
Vector OA = (4; 6) ; |OA| = 7.2111
Vector OB = (8; 3) ; |OB| = 8.544
Scalar product OA .OB = 50
Angle ∠ AOB = 35°45'14″ = 0.624 rad