Line slope calculator 3x+4y=36


Enter coordinates of two different points:

Straight line given by points A[4; 6] and B[8; 3]

Calculation:

Slope-intercept form of line: y = -0.75x+9

Canonical form of the line equation: 3x+4y-36 = 0

Parametric form of the line equation:
x = 4t+4
y = -3t+6      ; t ∈ R

Slope: m = -0.75

Slope angle of line: φ = -36°52'12″ = -0.6435 rad

X intercept: x0 = 12

Y intercept: y0 = q = 9

Distance line from the origin: d0 = 7.2

The length of the segment AB: |AB| = 5

Vector: AB = (4; -3)

Normal vector: n = (3; 4)

Midpoint of the segment AB: M = [6; 4.5]

Perpendicular Bisector equation: 4x-3y-10.5 = 0


Vector OA = (4; 6) ;   |OA| = 7.2111
Vector OB = (8; 3) ;   |OB| = 8.544
Scalar product OA .OB = 50
Angle ∠ AOB = 35°45'14″ = 0.624 rad