Line slope calculator x+4y=28


Enter coordinates of two different points:

Straight line given by points A[4; 6] and B[8; 5]

Calculation:

Slope-intercept form of line: y = -0.25x+7

Canonical form of the line equation: x+4y-28 = 0

Parametric form of the line equation:
x = 4t+4
y = -t+6      ; t ∈ R

Slope: m = -0.25

Slope angle of line: φ = -14°2'10″ = -0.245 rad

X intercept: x0 = 28

Y intercept: y0 = q = 7

Distance line from the origin: d0 = 6.791

The length of the segment AB: |AB| = 4.1231

Vector: AB = (4; -1)

Normal vector: n = (1; 4)

Midpoint of the segment AB: M = [6; 5.5]

Perpendicular Bisector equation: 4x-y-18.5 = 0


Vector OA = (4; 6) ;   |OA| = 7.2111
Vector OB = (8; 5) ;   |OB| = 9.434
Scalar product OA .OB = 62
Angle ∠ AOB = 24°18'16″ = 0.4242 rad