Line slope calculator 4x-5y=-14
Straight line given by points A[4; 6] and B[9; 10]
Calculation:
Slope: m = 0.8Slope-intercept form of line: y = 0.8x+2.8
Canonical form of the line equation: 4x-5y+14 = 0
Parametric form of the line equation:
x = 5t+4
y = 4t+6 ; t ∈ R
Slope angle of line: φ = 38°39'35″ = 0.6747 rad
X intercept: x0 = -3.5
Y intercept: y0 = q = 2.8
Distance line from the origin: d0 = 2.1864
The length of the segment AB: |AB| = 6.4031
Vector: AB = (5; 4)
Normal vector: n = (4; -5)
Midpoint of the segment AB: M = [6.5; 8]
Perpendicular Bisector equation: 5x+4y-64.5 = 0
Vector OA = (4; 6) ; |OA| = 7.2111
Vector OB = (9; 10) ; |OB| = 13.4536
Scalar product OA .OB = 96
Angle ∠ AOB = 8°17'50″ = 0.1448 rad