Line slope calculator 3x+5y=42


Enter coordinates of two different points:

Straight line given by points A[4; 6] and B[9; 3]

Calculation:

Slope-intercept form of line: y = -0.6x+8.4

Canonical form of the line equation: 3x+5y-42 = 0

Parametric form of the line equation:
x = 5t+4
y = -3t+6      ; t ∈ R

Slope: m = -0.6

Slope angle of line: φ = -30°57'50″ = -0.5404 rad

X intercept: x0 = 14

Y intercept: y0 = q = 8.4

Distance line from the origin: d0 = 7.2029

The length of the segment AB: |AB| = 5.831

Vector: AB = (5; -3)

Normal vector: n = (3; 5)

Midpoint of the segment AB: M = [6.5; 4.5]

Perpendicular Bisector equation: 5x-3y-19 = 0


Vector OA = (4; 6) ;   |OA| = 7.2111
Vector OB = (9; 3) ;   |OB| = 9.4868
Scalar product OA .OB = 54
Angle ∠ AOB = 37°52'30″ = 0.661 rad