Line slope calculator 2x+5y=38
Straight line given by points A[4; 6] and B[9; 4]
Calculation:
Slope: m = -0.4Slope-intercept form of line: y = -0.4x+7.6
Canonical form of the line equation: 2x+5y-38 = 0
Parametric form of the line equation:
x = 5t+4
y = -2t+6 ; t ∈ R
Slope angle of line: φ = -21°48'5″ = -0.3805 rad
X intercept: x0 = 19
Y intercept: y0 = q = 7.6
Distance line from the origin: d0 = 7.0564
The length of the segment AB: |AB| = 5.3852
Vector: AB = (5; -2)
Normal vector: n = (2; 5)
Midpoint of the segment AB: M = [6.5; 5]
Perpendicular Bisector equation: 5x-2y-22.5 = 0
Vector OA = (4; 6) ; |OA| = 7.2111
Vector OB = (9; 4) ; |OB| = 9.8489
Scalar product OA .OB = 60
Angle ∠ AOB = 32°20'51″ = 0.5646 rad