Line slope calculator 2x+5y=38


Enter coordinates of two different points:

Straight line given by points A[4; 6] and B[9; 4]

Calculation:

Slope-intercept form of line: y = -0.4x+7.6

Canonical form of the line equation: 2x+5y-38 = 0

Parametric form of the line equation:
x = 5t+4
y = -2t+6      ; t ∈ R

Slope: m = -0.4

Slope angle of line: φ = -21°48'5″ = -0.3805 rad

X intercept: x0 = 19

Y intercept: y0 = q = 7.6

Distance line from the origin: d0 = 7.0564

The length of the segment AB: |AB| = 5.3852

Vector: AB = (5; -2)

Normal vector: n = (2; 5)

Midpoint of the segment AB: M = [6.5; 5]

Perpendicular Bisector equation: 5x-2y-22.5 = 0


Vector OA = (4; 6) ;   |OA| = 7.2111
Vector OB = (9; 4) ;   |OB| = 9.8489
Scalar product OA .OB = 60
Angle ∠ AOB = 32°20'51″ = 0.5646 rad