Line slope calculator 5x+6y=68
Straight line given by points A[4; 8] and B[10; 3]
Calculation:
Slope: m = -0.8333Slope-intercept form of line: y = -0.8333x+11.3333
Canonical form of the line equation: 5x+6y-68 = 0
Parametric form of the line equation:
x = 6t+4
y = -5t+8 ; t ∈ R
Slope angle of line: φ = -39°48'20″ = -0.6947 rad
X intercept: x0 = 13.6
Y intercept: y0 = q = 11.3333
Distance line from the origin: d0 = 8.7065
The length of the segment AB: |AB| = 7.8102
Vector: AB = (6; -5)
Normal vector: n = (5; 6)
Midpoint of the segment AB: M = [7; 5.5]
Perpendicular Bisector equation: 6x-5y-14.5 = 0
Vector OA = (4; 8) ; |OA| = 8.9443
Vector OB = (10; 3) ; |OB| = 10.4403
Scalar product OA .OB = 64
Angle ∠ AOB = 46°44'9″ = 0.8157 rad