Line slope calculator 8x+y=40


Enter coordinates of two different points:

Straight line given by points A[4; 8] and B[5; 0]

Calculation:

Slope-intercept form of line: y = -8x+40

Canonical form of the line equation: 8x+y-40 = 0

Parametric form of the line equation:
x = t+4
y = -8t+8      ; t ∈ R

Slope: m = -8

Slope angle of line: φ = -82°52'30″ = -1.4464 rad

X intercept: x0 = 5

Y intercept: y0 = q = 40

Distance line from the origin: d0 = 4.9614

The length of the segment AB: |AB| = 8.0623

Vector: AB = (1; -8)

Normal vector: n = (8; 1)

Midpoint of the segment AB: M = [4.5; 4]

Perpendicular Bisector equation: x-8y+27.5 = 0


Vector OA = (4; 8) ;   |OA| = 8.9443
Vector OB = (5; 0) ;   |OB| = 5
Scalar product OA .OB = 20
Angle ∠ AOB = 63°26'6″ = 1.1071 rad