Line slope calculator 6x+y=32


Enter coordinates of two different points:

Straight line given by points A[4; 8] and B[5; 2]

Calculation:

Slope-intercept form of line: y = -6x+32

Canonical form of the line equation: 6x+y-32 = 0

Parametric form of the line equation:
x = t+4
y = -6t+8      ; t ∈ R

Slope: m = -6

Slope angle of line: φ = -80°32'16″ = -1.4056 rad

X intercept: x0 = 5.3333

Y intercept: y0 = q = 32

Distance line from the origin: d0 = 5.2608

The length of the segment AB: |AB| = 6.0828

Vector: AB = (1; -6)

Normal vector: n = (6; 1)

Midpoint of the segment AB: M = [4.5; 5]

Perpendicular Bisector equation: x-6y+25.5 = 0


Vector OA = (4; 8) ;   |OA| = 8.9443
Vector OB = (5; 2) ;   |OB| = 5.3852
Scalar product OA .OB = 36
Angle ∠ AOB = 41°38'1″ = 0.7266 rad