Line slope calculator 5x+y=28
Straight line given by points A[4; 8] and B[5; 3]
Calculation:
Slope: m = -5Slope-intercept form of line: y = -5x+28
Canonical form of the line equation: 5x+y-28 = 0
Parametric form of the line equation:
x = t+4
y = -5t+8 ; t ∈ R
Slope angle of line: φ = -78°41'24″ = -1.3734 rad
X intercept: x0 = 5.6
Y intercept: y0 = q = 28
Distance line from the origin: d0 = 5.4913
The length of the segment AB: |AB| = 5.099
Vector: AB = (1; -5)
Normal vector: n = (5; 1)
Midpoint of the segment AB: M = [4.5; 5.5]
Perpendicular Bisector equation: x-5y+23 = 0
Vector OA = (4; 8) ; |OA| = 8.9443
Vector OB = (5; 3) ; |OB| = 5.831
Scalar product OA .OB = 44
Angle ∠ AOB = 32°28'16″ = 0.5667 rad