Line slope calculator 3x+y=20


Enter the coordinates of two different points:
Line slope diagram

Straight line given by points A[4; 8] and B[5; 5]

Calculation:

Slope: m = -3

Slope-intercept form of line: y = -3x+20

Canonical form of the line equation: 3x+y-20 = 0

Parametric form of the line equation:
x = t+4
y = -3t+8      ; t ∈ R

Slope angle of line: φ = -71°33'54″ = -1.249 rad

X intercept: x0 = 6.6667

Y intercept: y0 = q = 20

Distance line from the origin: d0 = 6.3246

The length of the segment AB: |AB| = 3.1623

Vector: AB = (1; -3)

Normal vector: n = (3; 1)

Midpoint of the segment AB: M = [4.5; 6.5]

Perpendicular Bisector equation: x-3y+15 = 0

Vector OA = (4; 8) ;   |OA| = 8.9443
Vector OB = (5; 5) ;   |OB| = 7.0711
Scalar product OA .OB = 60
Angle ∠ AOB = 18°26'6″ = 0.3218 rad