Line slope calculator 3x+2y=28


Enter coordinates of two different points:

Straight line given by points A[4; 8] and B[6; 5]

Calculation:

Slope-intercept form of line: y = -1.5x+14

Canonical form of the line equation: 3x+2y-28 = 0

Parametric form of the line equation:
x = 2t+4
y = -3t+8      ; t ∈ R

Slope: m = -1.5

Slope angle of line: φ = -56°18'36″ = -0.9828 rad

X intercept: x0 = 9.3333

Y intercept: y0 = q = 14

Distance line from the origin: d0 = 7.7658

The length of the segment AB: |AB| = 3.6056

Vector: AB = (2; -3)

Normal vector: n = (3; 2)

Midpoint of the segment AB: M = [5; 6.5]

Perpendicular Bisector equation: 2x-3y+9.5 = 0


Vector OA = (4; 8) ;   |OA| = 8.9443
Vector OB = (6; 5) ;   |OB| = 7.8102
Scalar product OA .OB = 64
Angle ∠ AOB = 23°37'46″ = 0.4124 rad