Line slope calculator 3x+2y=28
Straight line given by points A[4; 8] and B[6; 5]
Calculation:
Slope: m = -1.5Slope-intercept form of line: y = -1.5x+14
Canonical form of the line equation: 3x+2y-28 = 0
Parametric form of the line equation:
x = 2t+4
y = -3t+8 ; t ∈ R
Slope angle of line: φ = -56°18'36″ = -0.9828 rad
X intercept: x0 = 9.3333
Y intercept: y0 = q = 14
Distance line from the origin: d0 = 7.7658
The length of the segment AB: |AB| = 3.6056
Vector: AB = (2; -3)
Normal vector: n = (3; 2)
Midpoint of the segment AB: M = [5; 6.5]
Perpendicular Bisector equation: 2x-3y+9.5 = 0
Vector OA = (4; 8) ; |OA| = 8.9443
Vector OB = (6; 5) ; |OB| = 7.8102
Scalar product OA .OB = 64
Angle ∠ AOB = 23°37'46″ = 0.4124 rad