Line slope calculator 7x+3y=52


Enter coordinates of two different points:

Straight line given by points A[4; 8] and B[7; 1]

Calculation:

Slope-intercept form of line: y = -2.3333x+17.3333

Canonical form of the line equation: 7x+3y-52 = 0

Parametric form of the line equation:
x = 3t+4
y = -7t+8      ; t ∈ R

Slope: m = -2.3333

Slope angle of line: φ = -66°48'5″ = -1.1659 rad

X intercept: x0 = 7.4286

Y intercept: y0 = q = 17.3333

Distance line from the origin: d0 = 6.8279

The length of the segment AB: |AB| = 7.6158

Vector: AB = (3; -7)

Normal vector: n = (7; 3)

Midpoint of the segment AB: M = [5.5; 4.5]

Perpendicular Bisector equation: 3x-7y+15 = 0


Vector OA = (4; 8) ;   |OA| = 8.9443
Vector OB = (7; 1) ;   |OB| = 7.0711
Scalar product OA .OB = 36
Angle ∠ AOB = 55°18'17″ = 0.9653 rad