Line slope calculator 4x+3y=40
Straight line given by points A[4; 8] and B[7; 4]
Calculation:
Slope: m = -1.3333Slope-intercept form of line: y = -1.3333x+13.3333
Canonical form of the line equation: 4x+3y-40 = 0
Parametric form of the line equation:
x = 3t+4
y = -4t+8 ; t ∈ R
Slope angle of line: φ = -53°7'48″ = -0.9273 rad
X intercept: x0 = 10
Y intercept: y0 = q = 13.3333
Distance line from the origin: d0 = 8
The length of the segment AB: |AB| = 5
Vector: AB = (3; -4)
Normal vector: n = (4; 3)
Midpoint of the segment AB: M = [5.5; 6]
Perpendicular Bisector equation: 3x-4y+7.5 = 0
Vector OA = (4; 8) ; |OA| = 8.9443
Vector OB = (7; 4) ; |OB| = 8.0623
Scalar product OA .OB = 60
Angle ∠ AOB = 33°41'24″ = 0.588 rad