Line slope calculator 5x+4y=52
Straight line given by points A[4; 8] and B[8; 3]
Calculation:
Slope: m = -1.25Slope-intercept form of line: y = -1.25x+13
Canonical form of the line equation: 5x+4y-52 = 0
Parametric form of the line equation:
x = 4t+4
y = -5t+8 ; t ∈ R
Slope angle of line: φ = -51°20'25″ = -0.8961 rad
X intercept: x0 = 10.4
Y intercept: y0 = q = 13
Distance line from the origin: d0 = 8.121
The length of the segment AB: |AB| = 6.4031
Vector: AB = (4; -5)
Normal vector: n = (5; 4)
Midpoint of the segment AB: M = [6; 5.5]
Perpendicular Bisector equation: 4x-5y+3.5 = 0
Vector OA = (4; 8) ; |OA| = 8.9443
Vector OB = (8; 3) ; |OB| = 8.544
Scalar product OA .OB = 56
Angle ∠ AOB = 42°52'44″ = 0.7484 rad