Line slope calculator 2x-5y=-32
Straight line given by points A[4; 8] and B[9; 10]
Calculation:
Slope: m = 0.4Slope-intercept form of line: y = 0.4x+6.4
Canonical form of the line equation: 2x-5y+32 = 0
Parametric form of the line equation:
x = 5t+4
y = 2t+8 ; t ∈ R
Slope angle of line: φ = 21°48'5″ = 0.3805 rad
X intercept: x0 = -16
Y intercept: y0 = q = 6.4
Distance line from the origin: d0 = 5.9423
The length of the segment AB: |AB| = 5.3852
Vector: AB = (5; 2)
Normal vector: n = (2; -5)
Midpoint of the segment AB: M = [6.5; 9]
Perpendicular Bisector equation: 5x+2y-50.5 = 0
Vector OA = (4; 8) ; |OA| = 8.9443
Vector OB = (9; 10) ; |OB| = 13.4536
Scalar product OA .OB = 116
Angle ∠ AOB = 15°25'20″ = 0.2692 rad